4(2x^2-4)=3(x^2-8)

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Solution for 4(2x^2-4)=3(x^2-8) equation: 



4(2x^2-4)=3(x^2-8)

We move all terms to the left:

4(2x^2-4)-(3(x^2-8))=0

We multiply parentheses

8x^2-(3(x^2-8))-16=0



We calculate terms in parentheses: -(3(x^2-8)), so:

3(x^2-8)

We multiply parentheses

3x^2-24

Back to the equation:

-(3x^2-24)



We get rid of parentheses

8x^2-3x^2+24-16=0

We add all the numbers together, and all the variables

5x^2+8=0

a = 5; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·5·8
Δ = -160
Delta is less than zero, so there is no solution for the equation

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